18t=45t^2

Solution for 18t=45t^2 equation:

18t=45t^2

We move all terms to the left:

18t-(45t^2)=0

determiningTheFunctionDomain
-45t^2+18t=0

a = -45; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-45)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-45}=\frac{-36}{-90}
=2/5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-45}=\frac{0}{-90}
=0
$